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Please help with this functional differential equation.

7 Name: Anonymous 2021-04-17 17:54
y = Ax^3

So you're looking for

6Ax = A(Ax^3)^3

6x = (Ax^3)^3

6x = (Ax^3)(Ax^3)(Ax^3)

(6/A)x = x^9

6/A = x^8

A = 6/(x^8)

Plug it in the original equation

y = 6x^3 / x^8

y = 6 / x^5

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