1 Name: Anonymous 2021-04-17 16:27

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## Please help with this functional differential equation.

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1 Name: Anonymous 2021-04-17 16:27

2 Name: Anonymous 2021-04-17 16:35

y=0 meets these criteria, I think.

3 Name: Anonymous 2021-04-17 17:36

Let's say your function is y = Ax^2 + Bx + C

I think you're looking for a solution where

2A = A(Ax^2+Bx+C)^2 + B(Ax^2+Bx+C) + C

I think you're looking for a solution where

2A = A(Ax^2+Bx+C)^2 + B(Ax^2+Bx+C) + C

5 Name: Anonymous 2021-04-17 17:49

so y'=2ax+b

i guess b in this instance would be my constant so i would drop the c

i guess b in this instance would be my constant so i would drop the c

6 Name: Anonymous 2021-04-17 17:52

Quoted by: >>10

>>4

I am not sure, after the first der I would include a constant to the function

I am not sure, after the first der I would include a constant to the function

7 Name: Anonymous 2021-04-17 17:54

Quoted by: >>8,9

y = Ax^3

So you're looking for

6Ax = A(Ax^3)^3

6x = (Ax^3)^3

6x = (Ax^3)(Ax^3)(Ax^3)

(6/A)x = x^9

6/A = x^8

A = 6/(x^8)

Plug it in the original equation

y = 6x^3 / x^8

y = 6 / x^5

So you're looking for

6Ax = A(Ax^3)^3

6x = (Ax^3)^3

6x = (Ax^3)(Ax^3)(Ax^3)

(6/A)x = x^9

6/A = x^8

A = 6/(x^8)

Plug it in the original equation

y = 6x^3 / x^8

y = 6 / x^5

8 Name: Anonymous 2021-04-17 17:58

9 Name: Anonymous 2021-04-17 18:02

10 Name: Anonymous 2021-04-17 18:09

>>6

f(x) = e^x is the only function that is itself primed, if i remember right

f(x) = e^x is the only function that is itself primed, if i remember right

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find a general solution to this functional differential equation.

f ''(x) = f(f(x)) and there are general solutions

In other words find a function whose 2nd derivative is equal to the same function evaluated at all the points that make that function up.

For example f(f(x)) = ? when f(x) = x^2

is for x=2 ----> f(f(4)) ----> f(4) = 16 ----> f(16) = 256 and this has to be equal to its 2nd derivative