If so can you explain to me why the formula doesn't work with 2 doors? you have 2 doors you pick door 1 x= chance of the prize behind door 1 y = the chance of door 2 being opened before you picked door 1 g= given P(X&Y) = P(xgY) p(Y) P(y&x) = P(ygx) P(x) p(YgX) p(X) = P(XgY) p(Y) 1/1 1/2 = 1/1 1/2 IF we were to do it the same way that she does it in this video making y = the chance of any door being opened after you have picked door 1 we would have y = the chance of door 2 being opened after you picked door 1 = 1/1 p(YgX) p(X) = P(XgY) p(Y) 1/1 1/2 = 1/2 1/1 which doesn't make sense because if there are only two doors and door 2 is revealed to be incorrect then logically you would have a 100% chance of initially picking the correct door. https://www.youtube.com/watch?v=ugbWqWCcxrg&start=182 music thread too https://www.youtube.com/watch?v=qAMxr7JwxN4

https://i.imgur.com/h7357aB.png

If so can you explain to me why the formula doesn't work with 2 doors?

you have 2 doors

you pick door 1

x= chance of the prize behind door 1 y = the chance of door 2 being opened before you picked door 1 g= given

P(X&Y) = P(xgY) p(Y)

P(y&x) = P(ygx) P(x)

p(YgX) p(X) = P(XgY) p(Y)

1/1 1/2 = 1/1 1/2

IF we were to do it the same way that she does it in this video making y = the chance of any door being opened after you have picked door 1 we would have y = the chance of door 2 being opened after you picked door 1 = 1/1

p(YgX) p(X) = P(XgY) p(Y)

1/1 1/2 = 1/2 1/1

which doesn't make sense because if there are only two doors and door 2 is revealed to be incorrect then logically you would have a 100% chance of initially picking the correct door.

https://www.youtube.com/watch?v=ugbWqWCcxrg&start=182

music thread too

https://www.youtube.com/watch?v=qAMxr7JwxN4