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The solution?

1 Name: Anonymous 2021-04-14 15:26
Any monty hall problem "solution" knights around?

https://i.imgur.com/h7357aB.png

If so can you explain to me why the formula doesn't work with 2 doors?
you have 2 doors
you pick door 1
x= chance of the prize behind door 1 y = the chance of door 2 being opened before you picked door 1 g= given
P(X&Y) = P(xgY) p(Y)
P(y&x) = P(ygx) P(x)
p(YgX) p(X) = P(XgY) p(Y)
1/1 1/2 = 1/1 1/2
IF we were to do it the same way that she does it in this video making y = the chance of any door being opened after you have picked door 1 we would have y = the chance of door 2 being opened after you picked door 1 = 1/1
p(YgX) p(X) = P(XgY) p(Y)
1/1 1/2 = 1/2 1/1
which doesn't make sense because if there are only two doors and door 2 is revealed to be incorrect then logically you would have a 100% chance of initially picking the correct door.
https://www.youtube.com/watch?v=ugbWqWCcxrg&start=182
music thread too
https://www.youtube.com/watch?v=qAMxr7JwxN4

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